燃烧大脑脂肪

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settler
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Re: 燃烧大脑脂肪

#11

#11 帖子 settler »

jkxf 写了: 18 2月 2026, 21:08

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影子不对,阳光从左方照着树干,树干的阴影在右边,人的影子也应该朝右

 

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Re: 燃烧大脑脂肪

#12

#12 帖子 settler »

jkxf 写了: 28 2月 2026, 21:18

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找到的不要提前说答案

第10排右边第6

 

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Re: 燃烧大脑脂肪

#13

#13 帖子 resso »

jkxf 写了: 昨天, 20:55

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-81

 

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门前镜湖水
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Re: 燃烧大脑脂肪

#14

#14 帖子 门前镜湖水 »

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jkxf
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Re: 燃烧大脑脂肪

#15

#15 帖子 门前镜湖水 »

To find x^{27}, we can solve this algebraically using the properties of polynomials:

Step 1: Rearrange the Equation

Starting from the given equation:

Rearranging terms gives:

Step 2: Use the Sum of Cubes Identity

Recall the sum of cubes factorization:

Since x2 - x + 1 = 0, multiplying both sides by (x + 1) gives:

Step 3: Compute x^{27}

Now, express x^{27} in terms of x3:

Substitute x3 = -1:

Final Answer

-1

 

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Re: 燃烧大脑脂肪

#16

#16 帖子 resso »

门前镜湖水 写了: 今天, 10:21

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是个复数

 

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Re: 燃烧大脑脂肪

#17

#17 帖子 resso »

门前镜湖水 写了: 今天, 10:27

To find x^{27}, we can solve this algebraically using the properties of polynomials:

Step 1: Rearrange the Equation

Starting from the given equation:

Rearranging terms gives:

Step 2: Use the Sum of Cubes Identity

Recall the sum of cubes factorization:

Since x2 - x + 1 = 0, multiplying both sides by (x + 1) gives:

Step 3: Compute x^{27}

Now, express x^{27} in terms of x3:

Substitute x3 = -1:

Final Answer

-1

嗯,我昨天不小心算错了,我的算法是把x-1移相回去,然后两边同时平方

 

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